tag:blogger.com,1999:blog-2719106859199422273.post178713725071375766..comments2017-05-14T14:08:09.926+01:00Comments on Beautiful Stars: My Advice for PhD ApplicantsKaren Mastershttp://www.blogger.com/profile/12941003369342300418noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-2719106859199422273.post-48065161476628510162016-05-16T14:14:35.209+01:002016-05-16T14:14:35.209+01:00I apologize if this is bothersome, but I'm hav...I apologize if this is bothersome, but I'm having difficulty with the formula you gave on the above website. My math is wrong somehow and I cant seem to figure it out. Can you help? This is the original formula<br /><br />r = a(1-e*e) / (1+e cos(θ))<br /><br />Where a = 149.6 million Kilometers - Semi Major Axis to the Sun<br />e = .01672 or eccentricity of the Sun's orbit<br />θ = (number of days since perihelion * (365.25/360))<br /><br />So my calculation is <br />r=(149.6*(1- (.0672*.01672))) / 1+(.0672 cos(140*(365.25/360)))<br /><br />But this is not working out properly. Where am I wrong on this?<br /><br />John Allen Richterhttp://www.blogger.com/profile/02529922180796109091noreply@blogger.comtag:blogger.com,1999:blog-2719106859199422273.post-74759568023036315202016-05-02T20:36:04.303+01:002016-05-02T20:36:04.303+01:00Hello Karen. Recently I found your answer to calc...Hello Karen. Recently I found your answer to calculating the Earth's position relative to the Sun at curious.astro.cornell.edu. Those formulas are exactly what I need for a current study I am conducting on solar and lunar gravity. (http://curious.astro.cornell.edu/about-us/41-our-solar-system/the-earth/orbit/80-how-can-i-find-the-distance-to-the-sun-on-any-given-day-advanced) Thank you so much for that. I'm wondering if you have knowledge of similar calculations for calculating the zenith point on Earth relative to the Moon's orbit for any given date?johnallenrichterhttps://johnallenrichter.wordpress.com/noreply@blogger.com